Monday, February 19, 2007

COMPOUND INEQUALITIES

Post your questions on COMPOUND INEQUALITIES here.

12 comments:

Mr. Chamberlain said...

Check out the Video Tutor Lessons listed under section 6.3 on MathChamber!
MathChamber Unit 6

Daniel said...

Meh, I found the videos not all of that useful.

Mr. Chamberlain said...

Sorry to hear that. Do you have any questions I can help with?

Unknown said...

how do i slove...

-(1/3x + 3y) ≤ 3

i dont know how to slove it woth the negative... i think both become a negative because its like distributing a negative, but im not sure..

Unknown said...

ooops.. sorry wrong sectin, ill post it in the right one

Mr. Chamberlain said...

You are correct, sir.

-[(1/3)x + 3y] is the same thing as

-1[(1/3)x + 3y]... therefore, you simply distribute using the -1, or as you correctly stated it... you distribute the negative.

And when you multiply a bunch of terms by -1, the signs "flip"... positives become negatives and vice versa.

This is an important skill to master. Good question.

Mr. Chamberlain said...

oh, so the final answer is:

-[(1/3)x + 3y] = (-1/3)x - 3y

I always forget to answer the question! I find answers boring.

Daniel said...

Interesting theory, and I basically said the same thing in the other section. But you think answers are boring, eh? Do you believe this philosophy on tests?

Mr. Chamberlain said...

Well, I didn't say that answers weren't sometimes kinda-sorta important, but I prefer good process over good answers just about any day of the week (especially the days that end in "y").

Daniel said...

Ah, likewise interesting theory, which I completely agree with. However, if we were to have a day that did not end in "y" such as...Hibachi Sukula Im, answers wouldn't be necessary?

Mr. Chamberlain said...

Must you always state the obvious?

Daniel said...

Yes, I think from now on I shall, but I will now try to stop detracting from the original post idea/theme.