hi mr. c i have a question with the homework....it is a lot of problems (because a lot of problems deal with this) but i will use #18 (on page 356)
the system is: {x-2y=0 {3x-y=0
i converted them both into slope intersept form and then substituted the equtation and got this: 3x=x/2
i know how to solve this problem normally (solve the equation and then "plug in" the answer into the two problems and then solve those to get the coorindate points) but i have NO CLUE how to solve this since x is being divided by 2????
5 comments:
hi mr. c
i have a question with the homework....it is a lot of problems (because a lot of problems deal with this) but i will use #18 (on page 356)
the system is:
{x-2y=0
{3x-y=0
i converted them both into slope intersept form and then substituted the equtation and got this:
3x=x/2
i know how to solve this problem normally (solve the equation and then "plug in" the answer into the two problems and then solve those to get the coorindate points) but i have NO CLUE how to solve this since x is being divided by 2????
plz help?
Danielle, there is no difference between x/2 and 1/2 x, for ex. x=10, (10)/2=5 and 1/2(10)=5.
Your first step was SOLID.
Just remember, that sometimes the easy ones are the hardest (kinda like the horizontal and vertical lines).
Isn't x/2 equal to 1/2 of x? Couldn't you subtract 1/2 of x from both sides, leaving you with 5/2 x = 0?
Then multiply both sides by 2/5, right?
Give it a try. (Good question!)
Did you try graphing the lines? Where do they meet?
Oh, and thanks Soval, I think our responses crossed in cyberspace!
Okay, just doing the math student job.
-§o §aid §oval.
(trying to find my web identity)
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